go基础练习-上

 

一些练习题,简单回顾一下前五节的内容

Hello World 值 变量 常量 For 循环 If/Else 分支 Switch 分支结构 数组 切片 Map Range 遍历 函数 多返回值 变参函数 闭包 递归 指针 结构体 方法

一起学习:smiley:

Hello World

package main
import "fmt"
func main() {
    fmt.Println("hello world")
}
hello world

数值类型

package main

import "fmt"

func main() {

    fmt.Println("go" + "lang")

    fmt.Println("1+1 = ", 1+1)
    fmt.Println("7.0/3.0 = ", 7.0/3.0)

    fmt.Println(true && false)
    fmt.Println(true || false)
    fmt.Println(!true)
}
golang
1+1 =2
7.0/3.0 =2.3333333333333335
false
true
false

变量

package main

import "fmt"

func main() {

    var a = "initial"
    fmt.Println(a)

    var b, c int = 1, 2
    fmt.Println(b, c)

    var d = true
    fmt.Println(d)

    var e int
    fmt.Println(e)

    f := "short"
    fmt.Println(f)
}
initial
12
true
0
short

细节

1 2//注意哦,有空格的

常量

package main

import (
    "fmt"
    "math"
)

const s string = "constant"

func main() {
    fmt.Println(s)

    const n = 500000000

    const d = 3e20 / n
    fmt.Println(d)

    fmt.Println(int64(d))

    fmt.Println(math.Sin(n))
}
constant
6e+11
600000000000
-0.28470407323754404

注意

可以发现6e11或6e+11是6*10^11次方不是代数里的e(2.71828…)

For循环

package main

import "fmt"

func main() {

    i := 1
    for i <= 3 {
        fmt.Println(i)
        i = i + 1
    }

    for j := 7; j <= 9; j++ {
        fmt.Println(j)
    }

    for {
        fmt.Println("loop")
        break
    }

    for n := 0; n <= 5; n++ {
        if n%2 == 0 {
            continue
        }
        fmt.Println(n)
    }
}
1
2
3
7
8
9
loop
1
3
5

注意

func main() {

	i := 1
	for i <= 3 {
		fmt.Println(i)
		i = i + 1
	}

    //不知道会不会懵,以为i是值拷贝,所以出来后不会改变i的值
    //但这里的i是定义在外面的
	fmt.Println(i)
}
1
2
3
4

If/Else 分支

package main

import "fmt"

func main() {

    if 7%2 == 0 {
        fmt.Println("7 is even")
    } else {
        fmt.Println("7 is odd")
    }

    if 8%4 == 0 {
        fmt.Println("8 is divisible by 4")
    }

    if num := 9; num < 0 {
        fmt.Println(num, "is negative")
    } else if num < 10 {
        fmt.Println(num, "has 1 digit")
    } else {
        fmt.Println(num, "has multiple digits")
    }
}
7 is odd
8 is divisible by 4
has 1 digit

注意

Go 没有三目运算符, 即使是基本的条件判断,依然需要使用完整的 if 语句。

Switch 分支结构

package main

import (
    "fmt"
    "time"
)

func main() {

    i := 2
    fmt.Print("write ", i, " as ")
    switch i {
    case 1:
        fmt.Println("one")
    case 2:
        fmt.Println("two")
    case 3:
        fmt.Println("three")
    }

    switch time.Now().Weekday() {
    case time.Saturday, time.Sunday:
        fmt.Println("It's the weekend")
    default:
        fmt.Println("It's a weekday")
    }

    t := time.Now()
    switch {
    case t.Hour() < 12:
        fmt.Println("It's before noon")
    default:
        fmt.Println("It's after noon")
    }

    whatAmI := func(i interface{}) {
        switch t := i.(type) {
        case bool:
            fmt.Println("I'm a bool")
        case int:
            fmt.Println("I'm an int")
        default:
            fmt.Printf("Don't know type %T\n", t)
        }
    }
    whatAmI(true)
    whatAmI(1)
    whatAmI("hey")
}
write  2  as two
It's a weekday
It's after noon
I'm a bool
I'm an int
Don't know type string

补充

//whatAmI是定义了个函数
whatAmI := func(i interface{}) {//interface{} 任意类型
        switch t := i.(type) {  //i.(type)类型判断
        case bool:
            fmt.Println("I'm a bool")
        case int:
            fmt.Println("I'm an int")
        default:
            fmt.Printf("Don't know type %T\n", t)
        }
    }
whatAmI(true)
whatAmI(1)
whatAmI("hey")

数组

package main

import "fmt"

func main() {

    var a [5]int
    fmt.Println("emp:", a)

    a[4] = 100
    fmt.Println("set:", a)
    fmt.Println("get:", a[4])

    fmt.Println("len:", len(a))

    b := [5]int{1, 2, 3, 4, 5}
    fmt.Println("dcl:", b)

    var twoD [2][3]int
    for i := 0; i < 2; i++ {
        for j := 0; j < 3; j++ {
            twoD[i][j] = i + j
        }
    }
    fmt.Println("2d: ", twoD)
}
emp: [0 0 0 0 0]
set: [0 0 0 0 100]
get: 100
len: 5
dcl: [1 2 3 4 5]
2d:  [[0 1 2] [1 2 3]]

细节

//输出空格的细节
fmt.Println("2d: ", twoD)

切片

package main

import "fmt"

func main() {

    s := make([]string, 3)
    fmt.Println("emp:", s)

    s[0] = "a"
    s[1] = "b"
    s[2] = "c"
    fmt.Println("set:", s)
    fmt.Println("get:", s[2])

    fmt.Println("len:", len(s))

    s = append(s, "d")
    s = append(s, "e", "f")
    fmt.Println("apd:", s)

    c := make([]string, len(s))
    copy(c, s)
    fmt.Println("cpy:", c)

    l := s[2:5]
    fmt.Println("sl1:", l)

    l = s[:5]
    fmt.Println("sl2:", l)

    l = s[2:]
    fmt.Println("sl3:", l)

    t := []string{"g", "h", "i"}
    fmt.Println("dcl:", t)

    twoD := make([][]int, 3)
    for i := 0; i < 3; i++ {
        innerLen := i + 1
        twoD[i] = make([]int, innerLen)
        for j := 0; j < innerLen; j++ {
            twoD[i][j] = i + j
        }
    }
    fmt.Println("2d: ", twoD)
}
emp: [   ]	//不是[[] [] []]
set: [a b c]//不是[[a] [b] [c]]
get: c
3
apd: [a b c d e f]
cpy: [a b c d e f]
sl1: [c d e]//不是cdef
sl2: [a b c d e]//不是abcdef
sl3: [c d e f]//cdef
cdl: [g h i]//[[g] [h] [i]]
2d:  [[0] [1 2] [2 3 4]]//不是[[0 0 0] [1 2 0] [1 2 3]]

补充

string

string 是不可变的 byte 切片,底层是byte数组

//切片的内部结构
type slice struct {
    data uintptr
    len int
    cap int
}

var slice1 []type = make([]type, len)
//也可以简写为
slice1 := make([]type, len)//不是数组,[]string

数组

twoD := make([][]int, 3)
for i := 0; i < 3; i++ {
    innerLen := i + 1
    twoD[i] = make([]int, innerLen)
    for j := 0; j < innerLen; j++ {
        twoD[i][j] = i + j
    }
}
fmt.Println("2d: ", twoD)
[[0] [1 2] [2 3 4]]//不会自动补充,就分配那么多内存

slice[:]

左闭右开(取不到)

map

package main

import "fmt"

func main() {

    m := make(map[string]int)

    m["k1"] = 7
    m["k2"] = 13

    fmt.Println("map:", m)

    v1 := m["k1"]
    fmt.Println("v1: ", v1)

    fmt.Println("len:", len(m))

    delete(m, "k2")
    fmt.Println("map:", m)

    _, prs := m["k2"]
    fmt.Println("prs:", prs)

    n := map[string]int{"foo": 1, "bar": 2}
    fmt.Println("map:", n)
}
map: map[k1:7 k2:13]
v1: 7
len: 2
map: map[k1:7]
prs: false #不是nil
map: map[foo:1 bar:2]

Range

package main

import "fmt"

func main() {

    nums := []int{2, 3, 4}
    sum := 0
    for _, num := range nums {
        sum += num
    }
    fmt.Println("sum:", sum)

    for i, num := range nums {
        if num == 3 {
            fmt.Println("index:", i)
        }
    }

    kvs := map[string]string{"a": "apple", "b": "banana"}
    for k, v := range kvs {
        fmt.Printf("%s -> %s\n", k, v)
    }

    for k := range kvs {
        fmt.Println("key:", k)
    }

    for i, c := range "go" {
        fmt.Println(i, c)
    }
}
sum: 9
index: 1
a -> apple
b -> banana
key: a
key: b
0 103 #不是0 g,因为range 在字符串中迭代 unicode 码点
1 111 #不是1 o

函数

package main

import "fmt"

func plus(a int, b int) int {

    return a + b
}

func plusPlus(a, b, c int) int {
    return a + b + c
}

func main() {

    res := plus(1, 2)
    fmt.Println("1+2 =", res)

    res = plusPlus(1, 2, 3)
    fmt.Println("1+2+3 =", res)
}
1+2 = 3
1+2+3 = 6

多返回值

package main

import "fmt"

func vals() (int, int) {
    return 3, 7
}

func main() {

    a, b := vals()
    fmt.Println(a)
    fmt.Println(b)

    _, c := vals()
    fmt.Println(c)
}
3
7
7

变参函数

package main

import "fmt"

func sum(nums ...int) {
    fmt.Print(nums, " ")
    total := 0
    for _, num := range nums {
        total += num
    }
    fmt.Println(total)
}

func main() {

    sum(1, 2)
    sum(1, 2, 3)

    nums := []int{1, 2, 3, 4}
    sum(nums...)
}
[1 2] 3
[1 2 3] 6
[1 2 3 4] 10

闭包

package main

import "fmt"

func intSeq() func() int {
    i := 0
    return func() int {
        i++
        return i
    }
}

func main() {

    nextInt := intSeq()

    fmt.Println(nextInt())
    fmt.Println(nextInt())
    fmt.Println(nextInt())

    newInts := intSeq()
    fmt.Println(newInts())
}
1
2
3
1

Go 支持匿名函数, 并能用其构造 闭包。 匿名函数在你想定义一个不需要命名的内联函数时是很实用的。

intSeq 函数返回一个在其函数体内定义的匿名函数。 返回的函数使用闭包的方式 隐藏 变量 i。 返回的函数 隐藏 变量 i 以形成闭包。

递归

package main

import "fmt"

func fact(n int) int {
    if n == 0 {
        return 1
    }
    return n * fact(n-1)
}

func main() {
    fmt.Println(fact(7))

    var fib func(n int) int

    fib = func(n int) int {
        if n < 2 {
            return n
        }
        return fib(n-1) + fib(n-2)

    }

    fmt.Println(fib(7))
}
5040
13 #不是33,没有求和

指针

package main

import "fmt"

func zeroval(ival int) {
    ival = 0
}

func zeroptr(iptr *int) {
    *iptr = 0
}

func main() {
    i := 1
    fmt.Println("initial:", i)

    zeroval(i)
    fmt.Println("zeroval:", i)

    zeroptr(&i)
    fmt.Println("zeroptr:", i)

    fmt.Println("pointer:", &i)
}
initial: 1
zeroval: 1
zeroptr: 0
pointer: 0xc00000a0a8

结构体

package main

import "fmt"

type person struct {
    name string
    age  int
}

func newPerson(name string) *person {

    p := person{name: name}
    p.age = 42
    return &p
}

func main() {

    fmt.Println(person{"Bob", 20})

    fmt.Println(person{name: "Alice", age: 30})

    fmt.Println(person{name: "Fred"})

    fmt.Println(&person{name: "Ann", age: 40})

    fmt.Println(newPerson("Jon"))

    s := person{name: "Sean", age: 50}
    fmt.Println(s.name)

    sp := &s
    fmt.Println(sp.age)

    sp.age = 51
    fmt.Println(sp.age)
}
{Bob 20}
{Alice 30}
{Fred 0}
&{Ann 40} #不会输出地址ox...
&{Jon 42} #不会输出地址ox
Sean
50
51

方法

Go语言方法像是其他语言类一样,可以私有的

函数就不行

package main

import "fmt"

type rect struct {
    width, height int
}

func (r *rect) area() int {
    return r.width * r.height
}

func (r rect) perim() int {
    return 2*r.width + 2*r.height
}

func main() {
    r := rect{width: 10, height: 5}

    fmt.Println("area: ", r.area())
    fmt.Println("perim:", r.perim())

    rp := &r
    fmt.Println("area: ", rp.area())
    fmt.Println("perim:", rp.perim())
}
area:  50
perim: 30
area:  50
perim: 30

调用方法时,Go 会自动处理值和指针之间的转换。 想要避免在调用方法时产生一个拷贝,或者想让方法可以修改接受结构体的值, 你都可以使用指针来调用方法。